Question

[(x^n)^n-1/n]^1/n+1 is equal to.

Answer 1

$\frac{{({({x}^{n})}^{n}-\frac{1}{n})}^{1}}{n}+1$

$\frac{{({x}^{nn}-\frac{1}{n})}^{1}}{n}+1$

$\frac{{({x}^{{n}^{2}}-\frac{1}{n})}^{1}}{n}+1$

$\frac{{x}^{{n}^{2}}-\frac{1}{n}}{n}+1$