Question

X_ray defratons studies show that copper crystalises in an fcc unit cell with cell edge of 3.608×10^-8cm.The dencity of copper is 8.92g/cm3.Calculate the atomic mass of copper. Give the answer

Answer 1

In case of fcc lattice,number of atoms per unit cell,x=4 atoms

Therefore,M = (dNAa^3)/z

(8.92×6.023×10^23 × (3.608×10^−8)^3)^4 g/mol

⇒ 63.1g/mol

∴ Atomic mass of copper =63.1u

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Answer 2

${\huge{\underline{\underline{\mathcal{\red{♡ANSWER♡}}}}}}$.

• ❤..In case of ${fcc}$ lattice,number of atoms per unit cell, ${Z=4 atoms}$
• ❤.. Therefore,${M}$ =$\frac{dNA a^3}{z}$
• ❤..${8.92gcm^-3×6.022×10^23 atoms mol^-1×(3.608×10^-8cm)^3}{4 atoms}$
• ❤..${63.1g/mol}$
• ❤..${Atomic mass of copper = 63.1u}$.