X square minus 1 divided by x to the power 45 find the remainder
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Step-by-step explanation:
The remainder must be a polynomial of degree no greater than one.
remainder = r(x) = Ax + B
q(x)(x² - 1) + r(x) = x^45 (for some polynomial function q(x))
Let x = -1.
q(-1)[(-1)² - 1] + r(-1) = (-1)^45
0 + r(-1) = -1
-A + B = -1
Let x = 1.
q(1)[(1)² - 1] + r(1) = (1)^45
0 + r(1) = 1
A + B = 1
Now you have this system in A and B:
-A + B = -1
A + B = 1
A = 1, B = 0
(1)x + (0) = x
The remainder is x.
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