x-rays of wavelength 0.4500nm are scattered from free electrons in a target.what is the wavwlength of photons scattered at 60 degree relative to the incident ray
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By the equation of compton shift we can write
here given that
now plug in all values to above equation
so the wavelength will be 0.4512 nm
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From equation Δλ = h/mc [1-cos?]
= [(6.63×10-34 J.s) (1-cos 60°)]/[(9.11×10-31kg) (3.00×108 m/s)]
= 4.5 × 10-10 m
≈ 450 pm
From the above observation we conclude that, the Compton shift of the scatered rays would be 2.2 pm.
(b) The fractional energy loss frac is,
frac = [E-E'] / E
= [hf – hf '] / hf
= [c/λ – c/λ'] / [c/λ]
= [λ' - λ] / λ'
= Δλ / [λ+Δλ]
Substitution gives,
frac = [450 pm]/[45 pm+45. pm]
hope its help you
thanx abd be brainly...............................................
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