Question

x=root3+1 by 2 then what is the value of 4xcube+2xsquare-8x+7​

Answer 1

Answer:

here is your answer-

Step-by-step explanation:

x=$\sqrt3$+1/2

4($\sqrt3$+1)³ + 2(√3+1)² - 8(√3+1) +7

4(3√3+1) + 2(3+1) - 8√3 -8 +7

12√3 +4 +6+2 - 8√3 -8 +7

12√3 +11 - 8√3

4√3 +11=answer

hope it helps you!!

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Answer 2

Step-by-step explanation:

x=(root3+1)/2

x^2=((root3+1)/2)^2= (3+1+2root3)/4=(4+2root3)/4

x^3=((root3+1)/2)^3

=((root3)^3+3(roo3)^2 *1 +3(root3)* 1^2 +1^3) /2^3

=(3root3+9+3root3+1) /8

=(6root3+10) /8

1. 4x^3+2x^2-8x+7 = 4*(6root3+10)/8 +2*(4+2root3)/4

-8*(root3+1)/2+7

=(6root3+10)/2 +(4+2root3)/2 - (8root3+8)/2+7

=(6root3+10 +4+2root3- 8root3-8+14)/2

=20)/2

=10