Question

x sq +kx+6=(x+2)(x+3)

Answer 1

x*x + kx + 6 = x*x + 3x + 2x + 6
=> kx + 6 = 5x + 6
=> kx = 5x
=> k = 5

Answer 2

[x+2] is the factor of x^2 + kx + 6 
x+2=0
x=-2
p(-2)= (-2)^2 + k(-2) + 6 =0
        =4- 2k +6 =0
        =4+6=2k
        =10/2 =k
        =5 =k
 put the value of k in given polynomial
   =x^2 + 5k +6  
    =x^2 +3x +2x +6
    = x (x + 3) +2(x +3)
     = (x+3) +(x +2)