x square + 10x - 600 find the zeros
Answers
Answer:
Factoring x2-10x-600
The first term is, x2 its coefficient is 1 .
The middle term is, -10x its coefficient is -10 .
The last term, "the constant", is -600
Step-1 : Multiply the coefficient of the first term by the constant 1 • -600 = -600
Step-2 : Find two factors of -600 whose sum equals the coefficient of the middle term, which is -10 .
-600 + 1 = -599
-300 + 2 = -298
-200 + 3 = -197
-150 + 4 = -146
-120 + 5 = -115
-100 + 6 = -94
-75 + 8 = -67
-60 + 10 = -50
-50 + 12 = -38
-40 + 15 = -25
-30 + 20 = -10 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -30 and 20
x2 - 30x + 20x - 600
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-30)
Add up the last 2 terms, pulling out common factors :
20 • (x-30)
Step-5 : Add up the four terms of step 4 :
(x+20) • (x-30)
Which is the desired factorization
Equation at the end of step
1
:
(x + 20) • (x - 30) = 0
Step-by-step explanation:
hope it helps...