Question

x square + 1x - 56 factories​

Answer 1

Answer:

Step-by-step explanation:

The first term is, x2 its coefficient is 1 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -56

Step-1 : Multiply the coefficient of the first term by the constant 1 • -56 = -56

Step-2 : Find two factors of -56 whose sum equals the coefficient of the middle term, which is -1 .

-56 + 1 = -55

-28 + 2 = -26

-14 + 4 = -10

-8 + 7 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 7

x2 - 8x + 7x - 56

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-8)

Add up the last 2 terms, pulling out common factors :

7 • (x-8)

Step-5 : Add up the four terms of step 4 :

(x+7) • (x-8)

Which is the desired factorization

Equation at the end of step

1

:

(x + 7) • (x - 8) = 0

Answer 2

Step-by-step explanation:

$x {}^{2} + 1x - 56$

$x {}^{2} + 8x - 7x - 56$

$x(x + 8) - 7(x + 8)$

$(x + 8)(x - 7)$

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