Question

x square - 3 x minus 2 root 2 is equal to zero

Answer 1

${x}^{2} - 3x = 2 \sqrt{2}$
It can't be solved further
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Answer 2

Answer :



${x}^{2} - 3x - 2 \sqrt{2} = 0 \\ \\ solve \: the \: quadratic \:equation \: \: {ax}^{2} + bx + c = 0 \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{ - ( - 3) + \sqrt{ {( - 3)}^{2} - 4 \times 1 \times ( - 2) \sqrt{2} } }{2 \times 1}$
$x = \frac{ - ( - 3) + \sqrt{ {( - 3)}^{2} + 4 \times 2 \sqrt{2} } }{2} \\ \\ x = \frac{3 + \sqrt{ {( - 3)}^{2} + 4 \times 2 \sqrt{2} } }{2} \\ \\ x = \frac{3 + \sqrt{9 + 4 \times 2 \sqrt{2} } }{2} \\ \\ x = \frac{3 + \sqrt{9 + 8 \sqrt{2} } }{2} \\ \\ x = 3.75354$