Question

X square - 4 root 2 x + 6 is equal to zero solve it by sold it by quadratic equation

Answer 1

Answer:

hope this helps...:-)

Answer 2

⠀⠀⠀$\huge\underline{ \overline{ \bf{ \purple{QUESTION}}}}$

X square - 4 root 2 x + 6 is equal to zero solve it by sold it by quadratic equation.

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⠀⠀⠀⠀$\huge\underline{ \underline{ \bf{ { \blue{ An{ \pink{sw{ \purple{er \: : = }}}}} }}}}$

$\large\underline{ \underline{ \green{ \bold {<strong>given</strong>}}}} = >$

equation:-$\longrightarrow \bf {\green{ {x}^{2} - 4 \sqrt{2} x + 6}}$

method used:-compleating the square method.

$\large\underline{ \underline{ \green{ \bold{solution}}}} = >$

move the constant to the right hand side and change it's sign.

$\longrightarrow \bf {\green{ {x}^{2} - 4 \sqrt{2} x = - 6}}$

Add $\rightarrow \bf {\green{ (\frac{4 \sqrt{2} }{2} )}}$to both the sides of the equation.

$\longrightarrow \bf {\green{ {x}^{2} - 4 \sqrt{2} x + ( \frac{4 \sqrt{2} }{2} ) {}^{2} }}$

using,

$\longrightarrow \rm{ \</strong><strong>p</strong><strong>i</strong><strong>n</strong><strong>k</strong><strong> { \boxed{\fbox{ {a}^{2} + {b}^{2} - 2b = (a - b) {}^{2} }}}}$

$\longrightarrow \rm{ \green{(x - \frac{4 \sqrt{2} }{2}) {}^{2} = - 6 + ( \frac{4 \sqrt{2} }{2} ){}^{2} }}$

$\longrightarrow \bf{ \green{(x - \frac{4 \sqrt{2} }{ 2} ) {}^{2} = 2}}$

$\longrightarrow \bf{ \green{(x - \frac{4 \sqrt{2} }{2} ) {}^{2} = 2}}$

⠀⠀$\longrightarrow \bf{ \boxed{ \fbox{ \pink{x = \sqrt{2} \: or \: x = 3 \sqrt{2} }}}}$

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