Question

x square +6x +7= 0 find the value of x

Answer 1

$\underline{\large\bf{\mathfrak{Hallo!}}}$

$= > {x}^{2} + 6x + 7 = 0 \\ \\ = > {x}^{2} + 6x + 9 - 2 = 0 \\ \\ = > {x}^{2} + 6x + 9 = 2 \\ \\ = > {x}^{2} + 3x + 3x + 9 = 2 \\ \\ = > x(x + 3) + 3(x + 3) = 2 \\ \\ = > (x + 3)(x + 3) = 2 \\ \\ = > {(x + 3)}^{2} = 2 \\ \\ = > x + 3 = ± \sqrt{2} \\ \\ = > x + 3 = \sqrt{2} \: \: \: \: or\: \: \: \: x + 3 = - \sqrt{2} \\ \\ = > x = \sqrt{2} - 3 \: \: \: \: or \: \: \: \: x = - \sqrt{2} - 3$

$\underline{\large\bf{\mathfrak{Hope \: this \: helps...:)}}}$

Answer 2

${x}^{2} + 6x + 7 = 0 \\ = > x = \frac{ - 6 + - \sqrt{ {6}^{2} - 4 \times 1 \times 7} }{2} \\ x1 = - 1.5 \: \: \: \: \: \: \: \: \: \: \: \: x2 = - 4.4$