x square - 7 x + 12 = 0
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Hello !!
We have a equation of second degree and we can solve with bhaskara formula.
x^2 - 7x + 12 = 0
Coeficients.
A = 1 ; B = -7 ; C = 12.
Find the discriminant.
D = b^2 - 4ac
D = (-7)^2 - 4 × 1 × 12
D = 49 - 4 × 12
D = 49 - 48
D = 1
Now, we find the roots.
x = (-b ± √D)/(2a)
x = (-(-7) ± √1)/(2 × 1)
x = (7 ± 1)/2
x' = (7 + 1)/2
x' = 8/2
x' = 4
x'' = (7 - 1)/2
x'' = 6/2
x'' = 3
Final result : the solution for quadratic equation is X = {4 , 3}.
I hope I have collaborated !
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