Question

x square +8x+12=0 I NEED this question in berif explanation​

Answer 1

Answer:

x²+8x+12=0

x²+6x+2x+12=0

x(x+6)+2(x+6)=0

(x+2)(x+6)=0

x+2=0 or x+6=0

x=-2 or x=-6

Answer 2

Answer:

${x}^{2} + 8x + 12 = 0 \\ {x}^{2} + 6x + 2x + 12 = 0 \\ x(x + 6) + 2(x + 6) = 0 \\ (x + 6)(x + 2) = 0 \\ x = - 6\: \\ x = - 2$

12 factors are 6 and 2 are suitable here.

And everything is common to do factorization