Math, asked by armankumar2241, 1 month ago

x square minus root 3 x minus 6

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Answered by gost04119

Answer:

$x {}^{2} - \sqrt{3x } - 6 \\ = x {}^{2} - 22 \sqrt{3} x + \sqrt{3} x - 6 \\ = x(x - 2 \sqrt{3} ) + \sqrt{3} (x - 2 \sqrt{3} ) \\ = (x - 2 \sqrt{3} )(x + \sqrt{3} )$

I think it is the correct answer

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x square minus root 3 x minus 6​

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x square minus root 3 x minus 6