Question

X square+y square-xy=0,then the value of x cube+y cube

Answer 1

Answer:

$\red { Value \:of \: x^{3} + y^{3}} \green {= 0}$

Step-by-step explanation:

$Given \: x^{2} -xy + y^{2} = 0\:--(1)$

$Value \:of \: x^{3} + y^{3}\\= (x+y)(x^{2} -xy +y^{3})$

$= (x+y) \times 0 \: [ From \:(1) ]$

$= 0$

Therefore.,

$\red { Value \:of \: x^{3} + y^{3}} \green {= 0}$

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Answer 2

Answer:

$x^3+y^3=0$

Step-by-step explanation:

$x^2+y^2-xy =0$

we know that

$x^3+y^3= (x+y)(x^2+y^2-xy)\\x^3+y^3= (x+y)0\\x^3+y^3=0$