Question

x squire - 2x -8 find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and coefficient ​

Answer 1

Answer:

x²-2x-8

=x²-(4-2)x-8

=x²-4x+2x-8

=x(x-4)+2(x-4)

=(x-4)(x+2)

to make it zero

x-4=0

so x=4

or

x+2=0

x=-2

-b

alpha+beta=-----------

a

-(-2)

4-2=-------------

1

2=2

c

alpha×beta=-----------------

a

--8

4×(-2)=---------------

1

-8=-8

Answer 2

Step-by-step explanation:

zeroes of the polynomial is +2 , - 4 for x

verification:

let ∆ and ¶ be the zeroes

hence

∆ × ¶ = -8

2 × -4 = -8

now

¶. +. ∆ = -2

2 + ( -4 ) =. -2

hence proved

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