Question

x=t^2 , y=t^3 , then d^2y/dx^2 is

Answer 1

y=t^3.

dy/dx=0.

t is constant

Answer 2

dy/dx = dy/dt / dx/dt = 3t^2/2t = 3t/2

now d2y/dx2 is d/dx (dy/dx) = d/dx (3t/2)

then apply implicit differentiation (by chain rule, dy/dx = dy/dt . dt/dx) since t is a variable:

d/dx (3/2t) = d/dt (3/2t) . dt/dx... note the dt's appear to cancel...

so you get 3/2. dt/dx.

Now x = t^2 so dx = 2t dt and dt/dx = 1/2t

therefore d2y/dx2 = 3/2 (1/2t) = 3t/4

plz mark it as brainliest...