Question

x=|t-3|.Find distance and displacement​ in first 4s

Answer 1

Answer:

We know that velocity is

dt

dx

=v=4t so dx=4tdt

integrating both sides we get ∫

x

1

x

2

dx=∫

t=2

t=4

4tdt

or displacement =x

2

−x

1

=2t

2

∣

2

4

=2(16−4)=24m