Question

X takes 3 hours more than y to walk 30 km but if x doubles his speed he is ahead of y by one and half hours find their speed of walking

Answer 1

let speed of X be = x km/hr and speed of Y = y km/hr A/Q  30/y + 3 = 30/x  and 30/y - 3/2 = 30/2x  now put 1/x= p  and 1/y = q so equations become  30q + 3 = 30p  ⇒ 10p-10q = 1......(1) and  30q - 3/2 = 15p   ⇒ 10q - 1/2 = 5 ⇒ 20q - 1 = 10 p  ⇒ 20q -10 p = 1....(2)  solving (1) and (2) gives  p =3/10  and q = 1/5  so x = 10/3 km/hr y = 5 km/hr #hope it helps #mark as brainliest pls