Question

x
$\frac{x}{3} - \frac{y}{2} + \frac{z}{8} = 1 \\ \\ \frac{2x}{3} + \frac{y}{4} + \frac{z}{2} = \frac{17}{4} \\ \\ \frac{x}{6} + \frac{3y}{2} + \frac{z}{4} = 3$
find x,y,z​

Answer 1

Answer:

I tried.

Step-by-step explanation:

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Answer 2

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