Question

x
$x^{2} + 7x + 12 = 0$
solve the quadratic equations​

Answer 1

Answer:

$\huge{\boxed{\rm{\red{Roots=-3,-4}}}}$

Step-by-step explanation:

Given equation is x²+7x+12=0

=>x²+3x+4x+12=0

=>x(x+3)+4(x+3)=0

=>(x+3)(x+4)=0

=>x+3=0(or)x+4=0

=>x=-3 and -4

The roots are -3 and -4

Answer 2

Answer:

roots are -4&-3

Step-by-step explanation: