Question

x
${x}^{2} - 92 {y }^{2} = 1 \: find \: the \: value \: of \: x \: and \: y$
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Answer 1

Answer:

$x { }^{2} - 92y {}^{2} = 1 \\ and \: we \: know \: \\ (x) {}^{2} - (\sqrt{92}y ) {}^{2} = 1 \\ and \: value = \sqrt{3} \: \: and \: \sqrt{5}$