Question

X

${x}^{2} + {y}^{2} = 7xy = show \: that \: 2log(x + y) = logx + logy + 2log3$
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Answer 1

Step-by-step explanation:

${x}^{2} + {y}^{2} = 7xy$

adding 2xy on both sides

${x}^{2} + {y}^{2} + 2xy = 9xy$

$(x + y) ^{2} = 9xy$

doing log on both sides

$log((x + y )^{2} ) = log(9xy)$

$2 log(x + y) = log(x) + log(y) + log(9)$

$2 log(x + y) = log(x) + log(y) + 2 log(3)$

hence prooved