Question

X varies directly as y square if x =7 when Y = to 1 find X when Y = 3

Answer 1

x is proportional to y^2
it can be written as
x=ky^2 where k is proportional constant.
if y=1 then x=7
putting in equation
7=k(1)^2
k=7
now equation is
x=7y^2
now y =3
x=7×(3)^2
x=7×9
x=63 ans

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Answer 2

The required value is 63.

GIVEN: X varies directly as y square if x =7 when Y = to 1.
TO FIND: Value of x when y = 3
SOLUTION:

As we are given in the question,

X varies directly as y square

Also,

x =7 when Y = to 1

As we know,

x is proportional to y²

it can be written as

x=ky² where k is a proportional constant whose value keeps on changing.

if y=1 then x=7

putting in equation

7=k(1)²

k=7

Therefore, putting the value of k as 7.

x=7y²

Now,

According to the question we put y =3

x=7(3)³

x=7×9

x=63

Therefore,

The required value of x is 63.

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