x(x-1)/2 = 25(49) - x(x-1)/2
find X
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What is the solution to x^2+y^2=25, xy=12?
So we are given 2 equations:
x2+y2=25
xy=12
And wish to find all possible solutions for this. Let us start by using the second equation and solving for y:
y=12x
Which gives:
x2+144x2=25
Throw around some numbers:
x2−25=−144x2
x4−25x2=−144
x4−25x2+144=0
So, complete the square to solve for x:
(x2−252)2−6254+144=0
(x2−252)2=6254−5764
(x2−252)2=494
x2−252=±72
x2=252±72
x2=25+72 or x2=25−72
x2=9 or x2=16
Since the highest polynomial is a grade four, this means four solutions, ±3 and ±4 . Plugging this in to the second equation, we finally get the four points:
(3,4) , (−3,−4) , (4,3) and (−4,−3) .
And with that, the answer can be simplified to ±(3,4) and ±(4,3) .
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