Math, asked by AkhilRanjan1, 1 year ago

x(x-1)(2x-1)(2x-3)-6 factorise

Answers

Answered by PADMINI
4

Given:

x(x-1)(2x-1)(2x-3)-6

To Find:

Factorise

Solution:

x(x-1)(2x-1)(2x-3)-6

=> ( x² - x ) (2x - 1) (2x - 3) - 6

=> x²(2x-1) -x(2x-1) (2x-3) - 6

=> ( 2x³ - x² - 2x² + x ) (2x - 3) - 6

=> 4x⁴ - 2x³ - 4x³ +2x² - 6x³ + 3x² + 6x² -3x - 6

=>  4x⁴ - 12x³ + 11x² - 3x - 6

Answered by chandresh126
5

Answer:

Equation => x (x-1) (2x-1) (2x-3) - 6 = 4x⁴ - 12x³ + 11x² - 3x - 6

Step-by-step explanation:

Hey Mate,

Given Equation,

=> x (x-1) (2x-1) (2x-3) - 6

=> ( x² - x ) (2x - 1) (2x - 3) - 6

=> ( 2x³ - x² - 2x² + x ) (2x - 3) - 6

=> 4x⁴ - 2x³ - 4x³ +2x² - 6x³ + 3x² + 6x² -3x - 6

=>  4x⁴ - 12x³ + 11x² - 3x - 6


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