Math, asked by singhsimmy313, 11 months ago

x/x^1-3=8x^-1 find the value of x

Answers

Answered by pallavisrinivas2004

1

Answer:

sorry I don't know the answer

Answered by nilesh102

0

hi mate,

solution:

x/x^1-3 = 8x^-1

x/x^-2 = 8 * 1/x

x^1 * ( x^- (-2) ) = 8/x

x^3 = 8/x

x^3 * x = 8

x^4 = 8

x = ∜ 8

The equation has two real solutions

These solutions are

x = ± ∜8 = ± 1.6818

Two solutions were found :

x = ± ∜8 = ± 1.6818

i hope it helps you..

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