x (x+1) +8 = (x+2) (2-2)
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x (x+1) +8 = (x+2) (2-2)
=x (x+1) +8 = (x+2) 0
=x (x+1) +8 = 0
= x^2 + x + 8 = 0
a=1, b= 1, c= 8
Using formula of Sridhar Acharya,
x = -b +- root ( b^2 - 4ac)
2a
x = - 1 +- root ( 1 - 32)
2
x= - 1 +- root(-31)
2
x = - 1 + root(-31) , - 1 - root(-31)
2 2
Answered by
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Answer:
x² + x +8 = (X+2) (2-2)d
Step-by-step explanation:
x²+X+8= 2x -2x +4 -4
x² + x +8 = 0
(x+ 2√2)² + x = 0
x+ 2√2 + x = 0²
2x+2√2=0
2x = 2√2
x = 2√2/2
x= √2
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