Question

X/x+1- x+1/x=1 1/2 find the value of x​

Answer 1

GIVEN :–

$\\ \implies \bf \dfrac{x}{x + 1} - \dfrac{x + 1}{x} = 1\dfrac{1}{2}$

TO FIND :–

• Value of 'x' = ?

SOLUTION :–

$\\ \implies \bf \dfrac{x}{x + 1} - \dfrac{x + 1}{x} = 1\dfrac{1}{2}$

$\\ \implies \bf \dfrac{(x)(x) - {(x + 1)}^{2} }{(x + 1)(x)} =\dfrac{3}{2}$

$\\ \implies \bf \dfrac{ {x}^{2} - {(x + 1)}^{2} }{(x + 1)(x)} =\dfrac{3}{2}$

$\\ \implies \bf \dfrac{ {x}^{2} - {x}^{2} - 1 - 2x}{(x + 1)(x)} =\dfrac{3}{2}$

$\\ \implies \bf \dfrac{- 1 - 2x}{ {x}^{2} + x} =\dfrac{3}{2}$

$\\ \implies \bf 2( - 1 - 2x) = 3( {x}^{2} + x)$

$\\ \implies \bf - 2 - 4x= 3{x}^{2} + 3x$

$\\ \implies \bf3{x}^{2} + 7x + 2 = 0$

$\\ \implies \bf3{x}^{2} + 6x + x + 2 = 0$

$\\ \implies \bf3x(x + 2) + 1(x +2)= 0$

$\\ \implies \bf(3x + 1)(x + 2)= 0$

$\\ \implies \large{ \boxed{ \bf x = - \dfrac{1}{3}, - 2}}$

Answer 2

Answer:

Displacement is the shortest distance between the initial and final position. It is a vector quantity i.e. it has both magnitude and direction. ... Displacement is the shortest distance between the initial and final position. It is a vector quantity i.e. it has both magnitude and direction