X(x+1)(x+2)(x+3)+1=0
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Answer:
x(×+1)(×+2)(×+3)+1=0
Step-by-step explanation:
×(×(×+2)+1(×+2)(×+3))+1
×(×^2+2× +1×+2 (×+3))+1
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this can be done by substitution method
x×(x+3) × (x+1)(x+2)
(x ² +3x )( x ² +3x+3)
let x ² +3x=m
m(m+3)=0
m ² +3m=0
m[m+3]=0
m=0 or m=-3
x ² +3x=0. or. x ² +3x=-3
x=0 or x=-3. x=-3 or x =-6
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