Question

x(x+1)+x(x+2)+x(x+3)+3=0

Answer 1

x(x+1)+x(x+2)+x(x+3)+3=0
or, x² + x + x² + 2x + x² + 3x + 3 = 0
or, 3x² + 6x + 3 = 0
or, x² + 2x + 1 = 0
or, (x + 1)² = 0
or, x + 1 = 0
or, x = (-1)

Hope this answer helped you :)

Answer 2

x(x+1)+x(x+2)+x(x+3)+3=0

x²+x+x²+2x+x²+3x+3=0

3x²+6x+3 =0


Here a=c ,so roots are reciprocal to each other


3x²+3x+3x+3=0

3x(x+1)+3(x+1)=0

3x+3=0,x+1=0

3x=-3,x=-1

x=-1,-1

so roots are (-1,-1)