Math, asked by anishkprateek, 5 hours ago

√x=(x-2) what is the no. of real solution​

Answers

Answered by Anonymous
3

Step-by-step explanation:

x=(x-2)^2

x=x^2 -4x +4

x^2 - 5x +4=0

(x-4)(x-1)=0

Thrfr, x=4,1 answer no. of real solutions is 2

MISZ

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