Math, asked by adityamangal09, 1 month ago

x-(x-2)-[(x-1)-(x-3)]=0. Then x=?

Answers

Answered by jc814170

1

x-(x-2)-[x-1-x+3]=0

x-(x-2)-[+2]=0

x-(x-2)-2=0

x-x+2-2=0

0=0

x=0

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