Question

x(x+2)(x^2-1)= - 1
Solve for x
​

Answer 1

Answer:

x(x+2)($x^{2}$−1)=−1

$x^{4}$ + $2x^{3}$ - $x^{2}$  - 2x = -1

Step 1: Subtract -1 from both sides.

$x^{4}$ + $2x^{3}$ - $x^{2}$ - 2x - (-1) = -1 - (-1)

$x^{4}$ + $2x^{3}$ - $x^{2}$ - 2x + 1 = 0

Step 2: Use quartic formula

x= −1.618034, 0.618034

Hope it helps