Question

x= X + h and y= Y+k is used in _________DE.

Answer 1

Step-by-step explanation:

Correct option is

B

[1+(dxdy)2]3=a2(dx2d2y)2

Given, (x−h)2+(y−k)2=a2       ...(i)

⇒2(x−h)+2(y−k)dxdy=0

⇒(x−h)+(y−k)dxdy=0     ...(ii)   

Again differentiating

(y−k)=−dx2d2y1+(dxdy)2

Putting in Eq. (ii), we get

x−h=−(y−k)dxdy

=dx2d2y[1+(dx