x^x√x=(x√x)^x Solve for x
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Take a log on both sides
log [(x)^xx] = log [(xx)^x]
```````````````log a^n = n*log a```````````
xx * log x= x * log [ xx]
``````````````log a*b = log a + log b`````````
xx * log x = x * [log x + 1/2 log x]
xx * log x = x * (3/2) * log x
x * log x cancel on both sides
x = 3/2
squaring on both sides
x =9/4
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Answered by
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Answer:
X=9/4
Step-by-step explanation:
log [(x)^xx] = log [(xx)^x]
```````````````log a^n = n*log a```````````
xx * log x= x * log [ xx]
``````````````log a*b = log a + log b`````````
xx * log x = x * [log x + 1/2 log x]
xx * log x = x * (3/2) * log x
x * log x cancel on both sides
x = 3/2
squaring on both sides
x =9/4
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