Math, asked by alu64, 6 months ago

x^x√x=(x√x)^x Solve for x​

Answers

Answered by Blackpinklovers
0

Take a log on both sides

log [(x)^xx] = log [(xx)^x]

```````````````log a^n = n*log a```````````

xx * log x= x * log [ xx]

``````````````log a*b = log a + log b`````````

xx * log x = x * [log x + 1/2 log x]

xx * log x = x * (3/2) * log x

x * log x cancel on both sides

x = 3/2

squaring on both sides

x =9/4

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Answered by Jeyapradha
0

Answer:

X=9/4

Step-by-step explanation:

log [(x)^xx] = log [(xx)^x]

```````````````log a^n = n*log a```````````

xx * log x= x * log [ xx]

``````````````log a*b = log a + log b`````````

xx * log x = x * [log x + 1/2 log x]

xx * log x = x * (3/2) * log x

x * log x cancel on both sides

x = 3/2

squaring on both sides

x =9/4

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