Question

x^x√x=(x√x)^x,then value of x is???​

Answer 1

Answer:

Assuming that x is not 0, raise both sides of the equation x^x√x=(x√x)^x to the power (1/x), you get:

(x)^√x = x√x and (x)^√x = (x)^3/2 Divide both sides by (x)^3/2:

(x)^[√x - 3/2] = 1 take the logarithm of both sides, you get:

[√x - 3/2] log(x) = 0 Therefore:

if √x - 3/2 = 0 then x = 9/4 and:

If log(x) = 0, then x = 1