Math, asked by sapnaverma2366, 1 month ago

x+(x-y)+y+(y-x) equals​

Answers

Answered by Thenavi
0

Answer:

x+(x-y)+y+(y-x)=x+x-y+y+y-x

=x+y

Answered by igibrahim07
0

Answer:

=y

Step-by-step explanation:

Simplifying

x(x + -1y) + y(y + -1x) = 0

(x * x + -1y * x) + y(y + -1x) = 0

Reorder the terms:

(-1xy + x2) + y(y + -1x) = 0

(-1xy + x2) + y(y + -1x) = 0

Reorder the terms:

-1xy + x2 + y(-1x + y) = 0

-1xy + x2 + (-1x * y + y * y) = 0

-1xy + x2 + (-1xy + y2) = 0

Reorder the terms:

-1xy + -1xy + x2 + y2 = 0

Combine like terms: -1xy + -1xy = -2xy

-2xy + x2 + y2 = 0

Solving

-2xy + x2 + y2 = 0

Solving for variable 'x'.

Factor a trinomial.

(x + -1y)(x + -1y) = 0

Subproblem 1

Set the factor '(x + -1y)' equal to zero and attempt to solve:

Simplifying

x + -1y = 0

Solving

x + -1y = 0

Move all terms containing x to the left, all other terms to the right.

Add 'y' to each side of the equation.

x + -1y + y = 0 + y

Combine like terms: -1y + y = 0

x + 0 = 0 + y

x = 0 + y

Remove the zero:

x = y

Simplifying

x = y

Subproblem 2

Set the factor '(x + -1y)' equal to zero and attempt to solve:

Simplifying

x + -1y = 0

Solving

x + -1y = 0

Move all terms containing x to the left, all other terms to the right.

Add 'y' to each side of the equation.

x + -1y + y = 0 + y

Combine like terms: -1y + y = 0

x + 0 = 0 + y

x = 0 + y

Remove the zero:

x = y

Simplifying

x = y

Solution

x = {y, y}

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