x(x+z)-y(y+z) factorize
Answers
Answered by
4
Hope u like my process
=====================
x(x+z) - y(y+z)
= x² +xz - y² - yz
= x² - y² + xz - yz
= (x + y)(x - y) + z(x - y)
__[since x² - y² =(x+y) (x-y)] ___
=(x-y) {(x+y) +z}
__[taking (x-y) common] __
= (x - y) (x+y+z)
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
=====================
x(x+z) - y(y+z)
= x² +xz - y² - yz
= x² - y² + xz - yz
= (x + y)(x - y) + z(x - y)
__[since x² - y² =(x+y) (x-y)] ___
=(x-y) {(x+y) +z}
__[taking (x-y) common] __
= (x - y) (x+y+z)
_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
Answered by
2
Hi Friend !!!!
Here is ur answer !!!
x(x+z)-y(y+z)
= x²-y²+xz-yz
= (x-y) (x+y)+z(x-y)
= (x-y) {x+y+z}
Hope it helps u : )
Here is ur answer !!!
x(x+z)-y(y+z)
= x²-y²+xz-yz
= (x-y) (x+y)+z(x-y)
= (x-y) {x+y+z}
Hope it helps u : )
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