{x:x²-5x+6=0} in roster method
Answers
Answered by
2
Step-by-step explanation:
Given set:-{x:x²-5x+6=0}
x²-5x+6=0
=>x²-2x-3x+6=0
=>x(x-2)+3(x-2)=0
=>(x-2)(x+3)=0
=>x-2 =0 or x+3=0
=>x=2 and x=-3
Roster form:-
A={2,-3}
Answered by
1
Answer:
P={2,3} is the answer if it is correctark it as brainliest
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