Question

x+xy+y=2+3√2 and x^2+y^2=6 find x+y+1

Answer 1

Answer:

a= x+y+z = 2 b= x^2+y^2+z^2 = 6 c= x^3+y^3 +z^3 = 8 * d= xy+yz+xz = (a^2-b)/2 = (2^2-6)/2 = -1 * e= xyz = (a^3-3ab+2c)/6 ...