Question

√x+y=11 and √y+x=7
Then find the value of x and y.

Answer 1

root x+y = 11 .........(1)
root y+x = 7...........(2)
From(1),
root x= 11÷root y
Substituting value of x in (2),
root y+ 11÷root y=7
(root y)²+ 11root y = 7
y + 11root y=7
Squarring both sides,
y²+ 121y= 49
y²+121y – 49=0
Factorise this equation and get the value of y and then substitute the value of y in equation (1) or (2), and get both the values .