X+y=11, x.y=18 so what is the x^2 + y^2?
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Answered by
3
(a+b)^2=a^2+2ab+b^2
(a+b)^2-2ab=a^2+b^2
11^2-2*18=a^2+b^2
121-36=a^2+b^2
a^2+b^2=85
Hope it helps!!
Plz mark as the brainliest
(a+b)^2-2ab=a^2+b^2
11^2-2*18=a^2+b^2
121-36=a^2+b^2
a^2+b^2=85
Hope it helps!!
Plz mark as the brainliest
wvaish:
Plz mark it as the brainliest
Answered by
1
(x+y)^2 = x^2+y^2+2xy
now,
x^2 + y^2 = (x+y)^2 - 2xy
substituting the above given values we get,
x^2 + y^2 = (11)^2 - 2(18)
= 121 - 36
= 85
now,
x^2 + y^2 = (x+y)^2 - 2xy
substituting the above given values we get,
x^2 + y^2 = (11)^2 - 2(18)
= 121 - 36
= 85
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