Math, asked by vpriyanshu572, 10 months ago

(x+y) = 11
xy = 2
x²+y² = ?

Answers

Answered by sumanvitummala
2

Answer:

x^2+y^2=117

Step-by-step explanation:

(x+y)=11

squaring on both sides

(x+y)^2=(11)^2

x^2+y^2+2xy=121

xy=2

=>x^2+y^2+2(2)=121

=>x^2+y^2=121-4

=>x^2+y^2=117

hope it's helfpul

mark me as branliest if the answer is correct

Answered by sheroneko
1

Step-by-step explanation:

(x + y) {}^{2}  = x {}^{2}  + 2xy + y {}^{2}  \\ x {}^{2}  + y {}^{2}  = (x + y) {}^{2}  - 2xy

On substituting the required values,

(x + y) {}^{2}  = 11 {}^{2}  - 2 \times 2 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 121 - 4  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 117

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Hope it helps....!

(=^.^=)

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