Question

x+y=11,xy=840 find x and y ​

Answer 1

Answer:

Step-by-step explanation:

x + √y = 7 and √x + y = 11

Consider

√x + y = 11

√x  = 11 - y

Squaring on both sides

x = 121 - 22y + y2

Put x = 121 - 22y + y2 in the equation x + √y = 7

Let √y = z

we get 121 + z4 - 22z2 + z = 7

We get factors z = ± 1, ± 2, ± 3, ± 6, ± 19, ± 57, ± 114

z = 3 satisfies the equation.

Now find the value of x and y we get x = 4 and y = 9