Question

X+y=13 xy=40 find the value of x-y

Answer 1

as we know that

(x+y)² =x²+y²+2xy

putting the value of x+y=13 and xy=40

(13)²=x²+y²+2(40)

160=x²+y²+80

x²+y²=160-80

=80

as we know

(x-y)²=x²+y²-2xy

putting the value of x²+y²=80and xy=40

(x-y)²=(-80)-2(40)

(x-y)² =80-80

(x-y)²= 0

x-y=√0

= 0

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