Question

(x,y) (2,0),(3,2) and (1,2) are the vertices of a parallelogram then (x,y) is​

Answer 1

Answer:

use the formula _/x1(y2-y3

Answer 2

The value of (x,y)=(0,0)

Explanation:

Let ABCD be the parallelogram with coordinates A (x,y) , B (2,0) , C (3,2) and D(1,2).

We know that the diagonals of a parallelogram bisects each other.

Then , Mid-point of AC = Mid-point of BD

i..e $(\dfrac{x+3}{2},\dfrac{y+2}{2})=(\dfrac{2+1}{2},\dfrac{0+2}{2})\\\\\Rightarrow\ \dfrac{x+3}{2}=\dfrac{2+1}{2}\ \ ,\ \ \dfrac{y+2}{2}=\dfrac{0+2}{2}\\\\\Rightarrow\ x+3=3\ ,\ y+2=2\\\\\Rightarrow\ x=0, y=0$

Hence, the value of (x,y)=(0,0)

# Learn more :

The sum of x-coordinates of the vertices of the triangle is 18 and that of y-coordinates is 24 then the coordinates of its centroid are..............

(a) (6,8)

(b) (8,6)

(c) (9,12)

(d) (12,9)​

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