Question

(x-y-2)^3-x^3+y^3+8

Dont write rubbish!!!
Answer only if u know.​

Answer 1

Answer:

x+y+2 = 0 x

3

+y

3

+8

Taking cube not on both sides

(x+y+2)

3

=0

x

3

+y

3

+8(x+y+2)(xy+2y+2x)=0.

x

3

+y

3

+8+(0)(xy+2y+2x)=0

x

3

+y

3

+8=0

solution