Question

(x+y) ^2 =64
Xy=15 then find x^2+y^2=
Tbh I don't understand da concept

Answer 1

This is your ans.
thankyou❤

Answer 2

Solution:-

Given:-

(x+y) ^2 =64

$= > {(x + y)}^{2 \times \frac{1}{2} } = {(8)}^{2 \times \frac{1}{2} }$

x + y = 8

xy = 15.

Required To Find : x^2 + y^2.

As we know that,

( x+y )^2 = x^2 + y^2 + 2xy

x^2 + y^2 = ( x + y )^2 - 2xy

= 8^2 - 2×15

= 64 - 30

x^2 + y^2 = 34.

Answer :-

x^2 + y^2 = 34