x+y=√2 and sinA x+cisA y = 1 are two equation find A
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Given
x + y = sqrt2 ---(1
sinA *x + cosA x = 1 ____(2
Solution
from ----(1
x + y = sqrt2
x/sqrt2 + y/sqrt2 = 1
We know that
Sin(π/4)= 1/sqrt2 = cos(π/4)
so
x sin(π/4) + y cos(π/4)= 1
cofficieant of x = sinπ/4
cofficieant of y = cosπ/4
Now from -----(1
cofficieant of x = sinA
cofficieant of y = cosA
so
sinA = sinπ/4
A = sin^-1sinπ/4
A = π/4
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